1. MnO4- = Mn+2(acid)
2. Zn = Zn+2
3. NO3- = NH3 (acid)
4. ClO3- = Cl- (basic)
5. VO+2 = V+2 (acidic)
6. Cr2O7-2= Cr+3(acidic)
Balance the following reactions.
1. Fe+3 + Sn+2 = Fe+2 + Sn+4
2. Cr2O7-2 + V+2 = Cr+3 + VO+2 (acidic)
3. Cl2 = Cl- + ClO3-(basic)
4. Cu + NO3- = NO + Cu+2 (acidic)
5. P2O5 + H2O = H3PO4
6. MnO4- +
V+2= Mn+2 + VO2+1(acidic)
3. 22.5 ml of 0.16 N MnO4- = ___________wt of Fe (Fe+2/Fe+3).
4. 1.67 g of KMnO4 dissolved to make 360 ml of solution = _____________ N
5.Indicate the equivalent weight
of each of the following substances that were weighed out.
| Substance weighed out. | Reaction: | Equivalent Weight |
| I2 | I2 to I- | |
| Fe(NH4)2(SO4)2(H2O)6 | Fe+2 to Fe+3 | |
| Na2S2O3 | S2O3-2 to S4O6-2 | |
| Na2C2O4 | C2O4-2 to CO2 |
6. IO4- + 8 H+ + __________e- = I- + 4 H2O
a) 1 b) 5 c) 6 d) 7 e) 8
7
What is the standard potential for a galvanic cell based on the reaction:
5 VO+2 + MnO4-
+ 11 H2O = 5 V(OH)4+ + Mn+2
+ 2 H+
Could this reaction be used
to analyze a sample for vanadium? Is the reaction spontaneous? How do you
know?
8. 22.5 ml of 0.16 N MnO4-= ___________eq of Sn (Sn+2=Sn+4)
9. Draw how the physical construction of a cell that has a short hand representation would look:
Zn| Zn+2(aq) || Br2(l),Br-(aq)|C(graphite)
Indicate the direction of flow of
the electrons in the wire and the flow of the ions in the salt bridge.
Calculate the standard potential of the cell.